Find the volume of a right circular cone that has a height of 16 m and a base with a circumference of 14.7 m. Round your answer to the nearest tenth of a cubic meter.

The volume of a right circular cone that has a height of 16 m and a base with a  circumference of 14.7 m is 3,620.62 m³

Step-by-step explanation:

The right cone (or cone of revolution, or right circular cone) is the solid of revolution formed by rotating a right triangle around one of its legs. The bottom circle of the cone is called the base. That is, a cone is a three-dimensional figure with a circular base. A curved surface connects the base and the vertex.

The volume of a 3-dimensional solid is the amount of space it occupies.

The volume V of a cone with radius r is one-third the area of the base B times the height h. This is:

where A=π*r²

Then: V= *π*r²*h

In this case r=14.7 m and h=16 m. Replacing:

V= *π*(14.7 m)²*16 m

Solving, you get:

V=3,620.62 m³

The volume of a right circular cone that has a height of 16 m and a base with a  circumference of 14.7 m is 3,620.62 m³

the answer to the question is a

step-by-step explanation:

it has the same slope and the same y-intercept.

y + 11 = -7/9(x - 18)

y + 11 =-7/9x + 14

b

y = -7/9x + 3

y-intercept (0, 3)