If one of the diagonals of a rectangle is 20cm and the difference between the length and the width is 4cm. What is the area of the triangle

192cm²

Step-by-step explanation:

The diagonal of the rectangle is expressed using the formula:

d = √l²+w²

l is the length

w is the width

Given d = 20

20 = √l²+w²

400 = l²+w² 1

Since the difference between the length and the width is 4cm, then;

l - w = 4 ... 2

l = 4 + w

Substitute equation 2 into 1;

400 = (4+w)²+w²

400 = 16 +8w + w² +w²

400 = 16 + 8w + 2w²

2w²+8w - 384 = 0

w²+4w - 192 = 0

w = -4±√4²-4(-192)/2

w = -4±√16+768/2

w = -4±28/2

w = -4+28/2

w = 24/2

w = 12

Since l = w+4

l = 12+4

l = 16

Area of the rectangle = 16 * 12

Area of the rectangle = 192cm²

hey there!

12 is twice as much as 6 because 6 goes into 12 2 times.

since the rabbit is twice as tall, we should multiply the weight of the first rabbit, 0.25, by 2.

0.25 x 2 = 0.5

therefore, the 12 inch chocolate rabbit weighs 0.5 lb, or half a pound.

hope this !

just needed some points but try socratic