Calvin is comparing the growth of two plants. Plant A started at a height of four inches and grows two inches each month. Plant B grew according to this equation, h = 4m + 2, where h, is the height after m, months. At what month will the two plants be the same height?

After 1 month, they will have same heights.

Step-by-step explanation:

Calvin is comparing the growth of two plants.

Plant A started at a height of four inches and grows two inches each month.

h'=4+2m

where

h' is height of plant after m months.

Plant B grew according to this equation, h = 4m + 2, where h, is the height after m, months.

We need to find at what month the plants have the same height. ATQ.

h = h'

4+2m = 4m + 2

Taking like terms together,

4-2 = 4m-2m

2=2m

m = 1

Hence, after 1 month, the plants will have same height.

f(x) = y

f(-3) = -5

step-by-step explanation:

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15