A point K is on the perpendicular bisector of a segment with endpoints at H and J. What must be true about point K? It is equidistant from H and J It falls on the h j It is at the midpoint of h j Not enough information is given

is equidistant from and .

Step-by-step explanation:

Given that the point which is on the perpendicular bisector of the line segment having endpoints at and .

The given situation can be represented as the diagram as attached in the answer area.

Referring to the :

(As it is the perpendicular bisector)

(As it is the perpendicular bisector)

Also, the side is the common side.

Therefore by congruence,

As per the properties of congruent triangles:

Side = Side

and are nothing but the distance of the point from the end points and which are proved to be equal to each other.

Therefore, we can conclude that:

is equidistant from and .

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answer: cos [   arcsin (3/5) - arccos (1/2) ] =

step-by-step explanation: × = 3/5 = 0.6--> x = 36.87 and x = 180 - 36.87 = 143.13 deg

cos y = 1/2 --> y = +- 60 deg a. cos (x - y) = cos (143.13 - 60) = cos 83,13  

=

0.12

b. cos (36.87 - 60) = cos (-23.23) = 0.92