Damarcus and Xavier went to the arcade to play their two favorite games. Damarcus played 4 rounds of game 1 and 6 rounds of game 2 for $18.00. Xavier played 5 rounds of each game for $20. What is the cost of game 1?

$3

Step-by-step explanation:

Given :

Let game 1 = x ; game 2 = y

4x + 6y = 18 - - - (1)

5x + 5y = 20 - - - (2)

From (2)

x + y = 4

y = 4 - x

Substitute y = 4-x in (1)

4x + 6(4 - x) = 18

4x + 24 - 6x = 18

-2x = 18 - 24

-2x = - 6

x = 6/2

x = 3

Game 1 cost $3

overpriced

step-by-step explanation:

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.