To the nearest tenth, what is the perimeter of the triangle with vertices at (−2, 3), (3, 6), and (2, −2)?

The perimeter of triangle = 20.3

Step-by-step explanation:

We need to find perimeter of the triangle with vertices at (−2, 3), (3, 6), and (2, −2)

The formula used to find perimeter is:

First we need to find length of each side using distance formula:

Find distance between (−2, 3), (3, 6)

We have:

Putting values and finding distance

So, The distance between (−2, 3), (3, 6) is 5.83

Find distance between (3, 6),(2,-2)

We have:

Putting values and finding distance

So, The distance between (3, 6),(2,-2) is 8.06

Find distance between (-2,3),(2,-2)

We have:

Putting values and finding distance

So, The distance between (-2, 3),(2,-2) is 6.40

So, The length of side 1 = 5.83

The length of side 2 = 8.06

The length of side 3 = 6.40

The perimeter of triangle will be:

So, The perimeter of triangle = 20.3

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hello from mrbilldoesmath!

answer:

x - 3

discussion:

x^2 - 9 = (x-3) (x+3)   so

(x^2-9)/ (x + 3) = x-3

you,

mrb