A pyrotechnician plans for two fireworks to explode together at the same height in the air. They travel at speeds shown below. Firework B is launched 0.25 s before Firework A. How many seconds after Firework B launches will both fireworks explode? Firework A 240 ft/s Firework B 200 ft/s

1.50 seconds

Step-by-step explanation:

Let x = Time taken by Firework A to explode( in seconds ).

Time taken by Firework B = x+ 0.25 seconds

Distance covered = Time × Speed

Distance covered by Firework A = 240 x

Distance covered by Firework B = 200 (x+0.25) = 200x+50

When both at same height , then

240x = 200x+50

⇒ 240x- 200x =50

⇒40x =50

⇒ x = 1.25

Total time = x+ 0.25 = 0.25+ 1.25 = 1.50 seconds

Hence. after Firework B launches it will take 1.50 seconds to launch.

b.) 160 miles on a 5 gallons car

step-by-step explanation:

240/10=24 miles/gallon

160/5=32 miles/gallon

30/1=30 miles/gallon

168/6= 28 miles/gallon

32 miles/gallon is the most amount, so this is the best.

step-by-step explanation: 4 cause 2+2=4