In ARST, mZR = (6x + 10)°, mZS = (2x + 5)°, and m_T = (3x – 11)'. Find m R.

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∠R = 106°

Step-by-step explanation:

Given that,

In ΔRST, ∠R = (6x + 10)°, ∠S = (2x + 5)°, and  ∠T = (3x – 11)°.

We need to find ∠R.

We know that, the sum of angles of a triangle is equal to 180°.

ATQ,

(6x + 10) + (2x + 5) + (3x – 11) = 180

Taking like terms,

6x+2x+3x = 180-10-5+11

11x = 176

x = 16

So,

∠R = (6x + 10) = 6(16) + 10

= 106°

Hence, ∠R = 106°

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

eventually after a few more steps, your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x