Please help to solve thos question.. Twenty-percent (20%) of Americans have no health insurance. Randomly sample n = 15 Americans. Let X denote the number in the sample with no health insurance. What is the probability that 3 of them have insurance?

0% probability that 3 of them have insurance

Step-by-step explanation:

For each American, there are only two possible outcomes. Either they have insurance, or they do not. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which is the number of different combinations of x objects from a set of n elements, given by the following formula.

And p is the probability of X happening.

Twenty-percent (20%) of Americans have no health insurance.

This means that 80% have insurance, so

Randomly sample n = 15 Americans.

This means that

What is the probability that 3 of them have insurance?

This is

0% probability that 3 of them have insurance

no

step-by-step explanation:

2-7=-5

7-2=5

when you combing like terms for ech expression, 5 and -5. these numbers are not equal to each other.

30 people weigh 160 pounds or more