Millions of Americans rely on caffeine to get them up in the morning. Here's nutritional data on some popular drinks at Ben's Beans coffee shop: Drink Type Calories Sugars (g) Caffeine (mg) Brewed coffee Hot 444 000 260260260 Caffè latte Hot 100100100 141414 757575 Caffè mocha Hot 170170170 272727 959595 Cappuccino Hot 606060 888 757575 Iced brewed coffee Cold 606060 151515 120120120 Chai latte Hot 120120120 252525 606060 The individuals in this data set are:

2)Ben Bean's Drinks

1) 4 variables, of which 1 is categorical

Step-by-step explanation:

Popular Drinks at Ben's Beans Coffee Shop

Drink                  Type           Calories      Sugars (g)        Caffeine (mg)

Brewed coffee      Hot             4                    0                        260

Caffè latte              Hot            100                  14                      75

Caffè mocha          Hot               170                 27                      95

Cappuccino         Hot               60                  8                        75

Iced brewed coffee Cold        60                 15                         120

Chai latte              Hot            120                 25                       60

The individuals in this data set are:

1) Ben Bean's  customers

2) Ben Bean's drinks

3) Caffeine Contents

This is a list of the coffee drinks not customers so option 2 is correct. Nor it deals with caffeine content.

The data set contains

1) 4 variables, of which 1 is categorical

2) 4 variables , of which 2 are categorical

3) 6 variables , of which 1 are categorical

4)  6 variables , of which 2 are categorical

Here option1 is correct because we have 4 variables ( type, calories, sugar, caffeine)out of which 1 ( type) is divided into 2 categories (hot or cold).

7.9m and 4.3°

step-by-step explanation:

let east be +x and north be +y, x = distance * cos θ, y = distance * sin θ  

for 3.5 south, y = -3.5  

for 8.2, x = 8.2 * cos 30 and y = 8.2 * sin 30  

for 15 west, x = -15  

total x = 8.2 * cos 30 – 15 ≈ -7.9  

total y = -3.5 + 8.2 * sin 30 = 0.6  

magnitude = [(8.2 * cos 30 – 15)^2 + 0.6^2)]^0.5  

the magnitude is approximately 7.9 m  

tan θ = y/x = 0.6/-7.9  

the angle is approximately 4.3˚ north of west