Marissa wants to sort 80 beads into 2 cases. The red case has 6 compartments, and the blue case has 8 compartments. How can she sort the beads so the compartments in each case hold the same number of beads and none are left over?

5.7 beads

Step-by-step explanation:

Marissa wants to sort 80 beads into 2 cases. The red case has 6 compartments, and the blue case has 8 compartments.

We are told in the Question that:

the compartments in each case hold the same number of beads and none are left over

Hence, let the number of beads in each compartments = x

Therefore:

8x + 6x = 80 beads

14x= 80 beads

x = 80 beads/14

x = 5.7142857143 beads

x ≈ 5.7 beads

Hence, she can sort the beads into 5.7 beads per compartments

answer: the answer is fre sha voca do

step-by-step explanation:

take the logarithm of both sides (the base of the log doesn't matter):

apply the exponent property - this says that :

distribute the log terms on both sides:

group like terms together:

divide through both sides by the coefficient on :

you can do some additional rewriting here using the properties of the logarithm to simplify things if you like: