A mix of 32 quarters and dimes totals $6.35. Find the system of equations that would help you answer the question and then find how many quarters (x) and dimes (y) you would have?

21 quarters and 11 dimes = 32 coins

Step-by-step explanation:

x + y = 32

0.25x + 0.10y = 6.35 [take the first equation and make it equal to x]

x = 32 - y [now take this equation and plug it in the above]

0.25 (32-y) + 0.10y = 6.35

8 - 0.25y + 0.10y = 6.35

8 - 0.15y = 6.35  [subtract 8 from both sides]

-0.15y = -1.65 [divide by -0.15 to isolate y]

y = 11 so there are 11 dimes

plug it into the first equation: x + 11 = 32; x = 21 so there are 21 quarters

the median here is 25. your lowest value is 14 and highest value is 48. to find the third quartile, find the medium number in between 25 and 48 which would be 42 i believe.

step-by-step explanation: