What are the solutions to the following system of equations? Select the correct answer below. y = x2 - 4x + 3
2x + y = 6
A) (-1,8) and (3,0)
B) (-1, 3) and (8,0)
C) (0,8) and (3, -1)
D) (3, 8) and (-1,0)

A

Step-by-step explanation:

we can conclude from the second equation that when

2x + y = 6 then y = 6 - 2x. so instead of y in the first equation we use 6 - 2x.

now the equation would look like this : 6 - 2x = x^2 - 4x + 3 .

then we bring everything to one side of the equation : x^2 - 2x - 3 .

now we'll have two results for x ( because x^2 - 2x - 3 = 0 has 2 answers )

one of them is -1 and other one is 3.

if we put them in the first equation we will have 8 and 0 for y.

so A is the answer

a

step-by-step explanation:

answer:

given the linear inequality :

add 2y to both sides we get;

simplify:

add 12 to both sides of an equation;

simplify:

divide both sides by 2 we get;

or

the related equation for the inequality equation [1] is;

y-intercepts defined as the graph crosses the y-axis.

substitute x =0 in [2] to solve for y;

y = 6

x-intercepts defined as the graph crosses the x-axis.

substitute value y = 0 to solve for x;

subtract 6 from both sides we get

multiply both sides by 2 we get;

or

x = -12

now, plot these point (0, 6) and (-12, 0) on graph as shown below and shade the graph below the solid line.