A 5.5-foot-tall woman walks at 8 ft/s toward a street light that is 22 ft above the ground. What is the rate of change of the length of her shadow when she is 20 ft from the street light? At what rate is the tip of her shadow moving?

Step-by-step explanation:

Given

length of shadow =22 ft

height of woman =5.5 ft

speed of woman

from the figure, we can write

at given instant

y=20 ft

so, using similar triangle properties

Again we can write

(f - g)(x) = 5x^3 - 3

step-by-step explanation:

rearrange these functions vertically, with like terms in separate columns:

f(x) = 5x^3 - 2

g(x) =         +1

now subtract, column by column:

(f - g)(x) = 5x^3 - 3

multiply length by height. multiply the length by the height, and then double the product. work out 10 x 10 results = 100 square inches, then work out 100 x 2 = 200. the answer is 200 square inches.

step-by-step explanation: