on the first of january 2014, carol invested some money in a bank account. The account pays 2.5% interest per year. On the first of january 2015 carol withdrew £1000 from the account. On the first of january 2016, she had £23517.60 in the account. Work out how much carol originally invested in the account

£23,360

Step-by-step explanation:

You can use algebra to solve this.

Assume that the original investment is x.

In the beginning of 2015 the balance had increased by 2.5% which is denoted as:

= 1.025x

Carol then withdrew a thousand:

= 1.025x - 1,000

This value then increased by 2.5% again by the beginning of 2016:

= 1.025 * (1.025x - 1,000)

Relevant expression therefore is:

1.025 *(1.025x - 1,000) = 23,517.60

1.025x - 1,000 = 23,517.60/1.025

1.025x = ‭22,944‬ + 1,000

x = 23,944/1.025

x = £23,360

step-by-step explanation:

|ab| = 1.4 = 4

h = 1.4 = 4

a(abc) area = 4.4 = 16/2 = 8

area of abc = 8 cm^2

good luck ! ; )

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step-by-step explanation: