Mathematics, 11.01.2021 02:20 colochaortiz20p7cajw

1. answer the three questions below about the quadrilateral: a. How could we find the perimeter below about the quadrilateral?

b. How might we calculate the area of this figure?

c. It looks like it might be a rectangle. What can we do to help us decide if it's a rectangle or a parallelogram?

1. answer the three questions below about the quadrilateral:

a. How could we find the perimeter b

Answers: 1

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Answer from: quentonwise

Before we begin, note that we need to use the distanse formula for everything to reach our conclusion. With that being said, here we go:

$\displaystyle \sqrt{[-x_1 + x_2]^2 + [-y_1 + y_2]^2} = d$

Using the ordered pairs $\displaystyle [3, -3]$ and $\displaystyle [4, -2]$ for instanse:

$\displaystyle \sqrt{[-3 + 4]^2 + [3 - 2]^2} = \sqrt{1^2 + 1^2} = \sqrt{2}$

Now, sinse the distanse between $\displaystyle [3, -3]$ and $\displaystyle [4, -2]$ is $\displaystyle \sqrt{2}$ units, then the distanse between $\displaystyle [1, 1]$ and $\displaystyle [0, 0]$ ALSO has to be $\displaystyle \sqrt{2}$ units. By definition, lettre c has already been answered for you because sinse it is a rectangle, if the two short sides are congruent, then the two long sides ALSO have to be congruent, but just in case you want to be sure [you do not trust your instincts], just simply re-use the distanse formula.

Using the ordered pairs $\displaystyle [1, 1]$ and $\displaystyle [4, -2]$ for instanse:

$\displaystyle \sqrt{[-1 + 4]^2 + [-1 - 2]^2} = \sqrt{3^2 + [-3]^2} = \sqrt{9 + 9} = \sqrt{18} = 3\sqrt{2}$

So there you have it. The length of both of the long sides is $\displaystyle 3\sqrt{2}$ units.

Now that we cleared all of that up, we can now find the perimetre and area of this rectangle:

$\displaystyle 2w + 2l = P$

$\displaystyle 2[\sqrt{2}] + 2[3\sqrt{2}] = 2\sqrt{2} + 6\sqrt{2} = 8\sqrt{2}$

The perimetre of this rectangle is $\displaystyle 8\sqrt{2}$ units.

$\displaystyle wl = A$

$\displaystyle [\sqrt{2}][3\sqrt{2}] = [3][2] = 6$

The area of this rectangle is $\displaystyle 6$ squared units.

You have now found what you were looking for.

** All rectangles are parallelograms because they both have two pairs of parallel and congruent sides, while vice versa is falce because a parallelogram does not have four congruent right angles, so it is safe to say that this is both a rectangle AND parallelogram, sinse the picture displayed is a rectangle.

I am joyous to assist you at any time. ☺️

Answer from: 123martinnnnn

9514 1404 393

a) compute and add up the side lengths

b) multiply length by width

c) compare the slopes of adjacent sides

Step-by-step explanation:

a) The perimeter of any figure is the sum of the lengths of its sides. It can be computed for a rectangle or parallelogram by adding the lengths of adjacent sides and multiplying the sum by 2.

In this graph, each grid square is 1/2 unit. The width of the rectangle is the diagonal of a square that is 1 unit on a side, so is √2 units. The length is 3 times that, so the perimeter is ...

P = 2(L+W)

P = 2(3√2 +√2) = 8√2 . . . . perimeter of the rectangle in units

b) The area is the product of the length and width.

A = LW

A = (3√2)(√2) = 6 . . . . area of the rectangle in square units

c) Each side lies on the diagonal of a unit square. The diagonals of a square are perpendicular, so the sides of this parallelogram are perpendicular. That means the figure is a rectangle.

The basic idea is to look at adjacent sides to see if they are perpendicular. Here, we have determined that using the properties of a square. One could compute "rise"/"run" for each side to see of the values are opposite reciprocals.

origin to B: rise/run = 1/1 = 1

B to C: rise/run = -3/3 = -1

Each of these values is the opposite reciprocal of the other: 1 = -1/-1.

Additional comment

This question seems to be about methods, not about numbers. We have given numbers anyway.

Answer from: Quest

when rotating a figure 180 degrees, imagine that you are able to take the figure and turn it clockwise or counterclockwise around a center point. to rotate a figure 180 degrees, you will need to apply the rule (x, y) → (-x, -y). start by using a coordinate grid with coordinates for each vertex of the figure. the center point of the coordinate grid is located at (0, 0), which is what you will rotate the figure around. write down the original coordinates of the shape you are going to rotate. then, apply the rule. for example, coordinate (1, 2) becomes (-1, -2). another example would be, coordinate (-4, -2) becoming (4, 2). after you change each original coordinate to the rotated coordinate, you will draw your new figure.

step-by-step explanation:

Identify the transformation that maps the figure with center (7, 1) onto itself. a) rotate 180° cloc

Answer from: Quest

since no one answered yet i will give it a shot, not completely sure tho.

i think it should be y=cos(x+2pi), (third answer, answer c)

good luck.

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