3 3
-6x + 6y= 6
-6x + 3y=-12
Solve the following system of equations. Write answer as an ordered pair (x, y), or write no
solution or infinitely many solutions if the system results in these cases. * "
(1 Point)
i’ll make u brainliest if u answer

The solution set is (5,6).

Step-by-step explanation:

Given equations are:

-6x + 6y= 6         Eqn 1

-6x + 3y=-12      Eqn 2

Subtracting Eqn 2 from Eqn 1

(-6x+6y)-(-6x+3y)= 6-(-12)

-6x+6y+6x-3y=6+12

3y = 18

Dividing both sides by 3

Putting y=6 in Eqn 1

-6x+6(6)=6

-6x+36=6

-6x=6-36

-6x=-30

Hence,

The solution set is (5,6).

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

~