How do i get the answer x= 3, -1 for equation (3/x^2)+ 2/x =1

Steps below

Step-by-step explanation:

(3/x²)+ 2/x =1   (x ≠ 0)

(3/x²) + 2x/x² = 1

(3 + 2x) / x² = 1

3 + 2x = x²

x² - 2x - 3 = 0

(x + 1) (x - 3) =0

x = -1 or x = 3

you didn't post any answer choices, so its not 100% clear what your teacher is looking for

however, log(15/7) is equivalent to log(15) - log(7)

i'm using the rule log(x/y) = log(x) - log(y)

answer: (-8,4) are the coordinates of a

step-by-step explanation:

let the side of square abcd is x .

thus the area of square abcd is .

now, by the diagram area of triangle ead= 1/2 × ea × ad = 1/2 × ea × x

( because ad is the side of square)

and, according to the question,

the areas of square abcd and right ead are equal.

⇒

⇒ea=2x

thus, ea: ab=2: 1

therefore, point a divides line segment eb into the ratio 2: 1.

⇒ by sectional formula coordinates of a are,

=

=

=(-8, 4)

thus the coordinates of a are (-8,4)