A person invests $1000 in a bank. The bank pays 6% interest compounded monthly. To the nearest tenth of a year, how long must the person leave the money in the bank until it reaches $3300

20 years approx

Step-by-step explanation:

Step one:

given data

Principal= $1000

rate= 6%

Final amount A= $3300

Required

Time t

Step two:

the expression for the compound interest is given data

A= P(1+r)^t

t = ln(A/P) / r

substitute

t= ln(3300/1000)/0.06

t= ln3.3/0.06

t= 1.193/0.06

t=19.88 years

t= 20 years approx

the answer is 510

step-by-step explanation:

15 • 13 = 195

15 • 12 = 180

15 • 5 = 75

12 • 5 = 60

195 + 180 = 375

375 + 75 = 450

450 + 60 = 510

x > 1.3

step by step:

8.5−0.9x> 9.8−1.9x

step 1: simplify both sides of the inequality.

−0.9x+8.5> −1.9x+9.8

step 2: add 1.9x to both sides.

−0.9x+8.5+1.9x> −1.9x+9.8+1.9x

1x+8.5> 9.8

step 3: subtract 8.5 from both sides.

1x+8.5−8.5> 9.8−8.5

1x> 1.3

step 4: divide both sides by 1.

1x/1 > 1.3/1