Triangle ABC has A(-3,6),B(2,1), and C(9,5) what the length of side AB? What the length BC what the length AC and what ABC

AB = 5√2

AC = √145

BC = √65

Step-by-step explanation:

Using the formula for calculating the distance between two points

D = √(x2-x1)²+(y2-y1)²

For AB A(-3,6),B(2,1),

AB = √(2+3)²+(1-6)²

AB = √(5)²+(-5)²

AB = √25+25

AB =  √50

AB = 5√2

For AC A(-3,6) and C(9,5)

AC = √(9+3)²+(5-6)²

AC = √(12)²+(-1)²

AC = √144+1

AC = √145

For BC B(2,1), and C(9,5)

BC = √(9-2)²+(5-1)²

BC = √(7)²+(4)²

BC = √49+16

BC = √65

Since All the sides are difference, hence triangle ABC is a scalene triangle

the correct answer is x/3+10≥32

hope this !

step-by-step explanation: so we look at the formula un = a + (n-1)d

un is the amount of seats

n is the nth term aka row number

a is the original sequence/row number

d is the difference between each term

so in this a=22 d=6 and n can remain as n because we are simply formjng a rule

lets put these in the equation

un=22+(n-1)(6)

this is your answer to part a

however

lets double check that this is correct, we'll try putting it into the second term

un=a+(n-1)d

u2=22+(2-1)(6)

u2=22+6

u2=28

as the question said the second row has 28 seats so now we know the formula we made is correct.

as for part b

un=a+(n-1)

its asking us to find a row with 100 seats.

remember un was the amount of seata so all we do is substitute this in.

un=100 a=22 d=6

un=a+(n-1)d

100=22+(n-1)(6)

so now we simplify to find n which is the row number.

100-22=22+(n-1)(6)-22

78=(n-1)(6)

78/6=(n-1)(6)/6

13=n-1

13+1=n-1+1

14=n

so now we know that in the 14th row there is 100 seats.

hope this and that you understood! its my first time using the app or anyone out on here : p its also me to revise so a bunch! ask more questions if you dont understand ☺