In ΔHIJ, the measure of ∠J=90°, HI = 88 feet, and IJ = 62 feet. Find the measure of ∠I to the nearest tenth of a degree.

Step-by-step explanation:

Firstly, we've to draw a triangle according to the givens. (See the attached file)

Then according to the Trigonometric Ratios:

Cos (I) = Adjacent / Hypotenuse

Cos (I) = 62 / 88

Cos (I) = 0.704

< I = Cos ⁻¹ (0.704)

< I = 45.2°

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the answer is d. (1.2, -4.7) on edgn

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