HELP PLS FOR BRAINLIEST! The electron and proton of a hydrogen atom are separated, on average, by a distance of about 5.3 x 10^-11 meters. Find the magnitudes of the electric force and the gravitational force that each particle exerts on the other.

And pls show work of how you did it :)

Electric force = 8.20x10⁻⁸ N

Gravitational force = 3.61x10⁻⁴⁷ N

Step-by-step explanation:

1. The electric force can be found using the following equation:

Where:

K: is the Coulomb's constant = 9x10⁹ N.m²/C²      

: is the charge of the proton = 1.6x10⁻¹⁹ C

: is the charge of the electron = -1.6x10⁻¹⁹ C

d: is the distance = 5.3x10⁻¹¹ m

Hence, the magnitude of the electric force is:

2. The gravitational force can be calculated as follows:

Where:

: is the electron's mass = 9.1x10⁻³¹ kg

: is the proton's mass = 1.67x10⁻²⁷ kg

G: is the gravitational constant = 6.67x10⁻¹¹ N.m²/kg²

Therefore, the gravitational force is:

As we can see, the gravitational force is much less than the electric force.

I hope it helps you!                                                      

x^6

step-by-step explanation:

this is correct because:

x-6=0

0*x=0

so

x^6

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.