Find the perimeter of a rectangle whose length is 4 cm greater than its height, and whose area is 60 cm².

Perimeter of the rectangle =  32 cm

Step-by-step explanation:

Explanation:-

Let the height of the rectangle = 'x' cm

Thus the length of the rectangle = x + 4 cm

Perimeter of the rectangle = 2 ( length + height )

Area of the rectangle = length X height

Given area of the rectangle = 60 cm²

( length X height ) = 60

( x + 4) x  =60

 x² + 4 x - 60 =0

 x² + 10 x- 6 x - 60 =0

x ( x+10) - 6 ( x + 10 ) =0

(x+10) ( x -6 ) = 0

x = -10  and x =6

we can choose x =6

The height of the rectangle(H) = 'x' = 6 cm

The length of the rectangle (L)= 6 + 4 = 10cm

Perimeter of the rectangle = 2 ( length + height )

                                           = 2 ( 10 + 6 )

                                          = 32 cm

∴ Perimeter of the rectangle = 32 cm

$30.32

step-by-step explanation:

65.00*.12=2.80

65.00-2.80=57.20

57.20*1.06=60.632

60.632/2=30.316