Part F Jeremy has heard a lot of people in the club
rock formation. Jeremy has set a limit that t
longer than 7 hours, so they have enough t
Will it be possible to climb a 950-foot rock
constraint? Explain why or why not.
My teacher said they would have enough time and the answer is 6.64 hours.
How is he getting the 6.64hrs?

The amount of minutes to climb 1 foot fheicht would take

Refer to the table below if needed. second quadrant third quadrant fourth quadrant sin(1800- - cos(180° -) tan(180°-e) =- tane cot(1800-0) 10 it to solo 888 sin(180° +c) = - sine cos(180° +) =- cose tan(180° +c) = tane cot(180° +o) = cote sec(180° + c) = - seco csc(180° +2) = - csce sin(360° -) =- sine cos(360° -) = cose tan(360° - e) =- tane cot(360° -) = -cote sec(360° -) = seco csc(360° -) = csco sec(180° -) = csc(180° -) = csca 1991 given that sine = 3/5 and lies in quadrant ii, find the following value. tane

Which of these angles are complementary? a. 45o and 45o b. 63o and 117o c. 45o and 135o d. 90o and 45o

Drag each equation to the correct location on the table. for each equation, determine the number of solutions and place on the appropriate field in the table.