Solve for the variable c in this equation: 3a(b+c)=d
A) c= d-3ab/3a
B) c=d+3ab/3a
C) c=d-3b/3a
D) c=d+3b/3a

if it's me I would pick etherbc are d I holp it helps

answer: (-8,4) are the coordinates of a

step-by-step explanation:

let the side of square abcd is x .

thus the area of square abcd is .

now, by the diagram area of triangle ead= 1/2 × ea × ad = 1/2 × ea × x

( because ad is the side of square)

and, according to the question,

the areas of square abcd and right ead are equal.

⇒

⇒ea=2x

thus, ea: ab=2: 1

therefore, point a divides line segment eb into the ratio 2: 1.

⇒ by sectional formula coordinates of a are,

=

=

=(-8, 4)

thus the coordinates of a are (-8,4)

the correct answers are 1, 2, 4, and 5! i just got it right!