Please help :))) I only need help with #7 because i am confuseddd

steps below and attachment

Step-by-step explanation:

5. attachment 1: red font values would be changed

6. 2nd attachment: g(x) = (x+3)²-9

   3rd attachment: h(x) = |g(x)|

7. -8≤x≤-6 or 0≤x≤2    g(x) = (x+3)²-9

  -6≤x≤0    f(x) = - (x + 3)² +9

x= -3 and

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

where a is the cube root of .

here   this is 27 and the cube root of 27 is 3. so we write using the form:

.

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

where a = 1, b=3, and c=9

this cubic has two complex roots.