A group of 30 dice are thrown. What is the probability that 5 of each of the values 1, 2, 3, 4, 5, 6 appear

the probability that 5 of each of the values 1, 2, 3, 4, 5, 6 appear is 0.0004

Step-by-step explanation:

Given that;

group of dice thrown (n) = 30

number of samples n(S) = 6³⁰

the probability that 5 of each of the values 1, 2, 3, 4, 5, 6 appear = ?

let A rep the event that 5 out of each of the values 1, 2, 3, 4, 5, 6 appear.

number of ways that 30 dice can be thrown is 30!

now, In the thirty throws from 1 to 30, there are;

FIVE 1's, FIVE 2's, FIVE 3's, FIVE 4's, FIVE 5's, FIVE 6's  characters to assign the dice.

which means n(A) = 30! / 5!5!5!5!5!5!

Now the probability that 5 of each of the values 1, 2, 3, 4, 5, 6 appear will be;

P(A) = 30!/5!5!5!5!5!5! / 6³⁰

P(A) = 30! / (5!)⁶ (6³⁰)

P(A) = 0.0004

Therefore the probability that 5 of each of the values 1, 2, 3, 4, 5, 6 appear is 0.0004

the workers who do no drive has no reasonable reason to buy gasoline due to they don't have anything to use it for

total amount of money that he should pay if he has not used his duty free exemption is $98

step-by-step explanation:

given a united states citizen returning to the states declares the following items at the customs office: 3 shirts at $8.50 each 2 dresses at $27.50 each 1 pair of gold cuff links at $17.50 per pair. we have to find how much he pay

cost of 3 shirts if one cost at $8.50 is

cost of 2 dresses if one cost at $27.50 is  

cost of 1 pair of gold cuff at $17.50

so, total amount of money that he should pay if he has not used his duty free exemption is   $25.5+$55+$17.50=$98