A bag contains 6 red blocks, 4 green blocks and 2 yellow blocks. Three blocks are taken from the bag, at random, without replacement. Calculate the probability that all three blocks will be the same colour

0.1090908

Step-by-step explanation:

Given :

R = red blocks

Y = yellow blocks

G = green. blocks

n(R) = 6 ; n(Y) = 2 ; n(G) = 4

Total blocks = 6 + 2 + 4 = 12

Probability that all blocks are of same color :

P(RRR) or P(YYY) or P(GGG)

P(RRR) = 6/12 * 5/11 * 4/10 = 0.0909090

P(YYY) = 2/12 * 1/11 * 0/10 = 0

P(GGG) = 4/12 * 3/11 * 2/10 = 0.0181818

Hence,

0.0909090 + 0 + 0.0181818

= 0.1090908

∠acb = 8°

step-by-step explanation:

∠xba lies on the circle and is half the measure of the intercepted arc ax

hence

measure of arc ax = 2 × 42° = 84°

∠acb is outside the circle and is

∠acb = (arcab - arcax ), hence

∠acb = 0.5 (100 - 84) = 0.5 × 16° = 8°