Toby's Trucking Company determined that the distance traveled per truck per year is normally distributed, with a mean of 45 thousand miles and a standard deviation of 10 thousand miles. What percentage of trucks can be expected to travel either below 30 or above 65 thousand miles in a year

0.089557

Step-by-step explanation:

Given thqt:

Mean, m = 45000

Standard = 10000

What percentage of trucks can be expected to travel either below 30 or above 65 thousand miles in a year

Below 30, 000

P(x < 30000)

Obtain the standardized score :

Z = (x - m) / s

Z = (30000 - 45000) / 10000

Z = - 15000 / 10000

Z = - 1.5

P(Z < - 1.5) = 0.066807

Above 65,000

P(x > 65000)

Obtain the standardized score :

Z = (x - m) / s

Z = (65000 - 45000) / 10000

Z = 20000 / 10000

Z = 2

P(Z > 2) = 0.02275 (Z probability calculator)

P(Z < - 1.5) + P(Z > 2)

0.066807 + 0.02275

= 0.089557

answer: option a.

step-by-step explanation:

you know that the quadrilateral opqr ( a four sided figure) is inscribed in circle. this means that all its vertices are on the circle.

then, by definition, the opposite angles of the quadrilateral are supplementary, this means that the sum of their measures is 180 degrees.

you can observe in the figure that the angles ∠opq   and the angle ∠orq   are opposite, therefore:

then, can be used to d to calculate the measure of ∠opq

- "runner b is moving at a slower rate."

- "the graphs shown are graphs of distance(km) against time(min).

the slopes of this graphs are are given by:

slope = (change in y)/(change in x)

= (change in distance)/(change in time)

this is the formula for finding the speed. so, the slope of these graphs represent the speed of the runner.

taking each division in the graph to represent 1 on both axis:

runner a ⇒ speed = (2-0)/(1-0)

= 2/1

= 2 km/min

runner b ⇒ speed = (3-0)/(3-0)

= 3/3

= 1 km/min

this shows that   runner b is moving at a slower rate."