What is the equation of the line that passes throguh (0,-1) and (-1,2) (case 1)

y = -3x - 1

Step-by-step explanation:

1) Find the slope of the line

Slope is -3

2) Plug the slope into a y-intercept form.

y = mx +b

y = -3x + b

3) Find b (which is the y-intercept) by plugging in any coordinates for the x and y.

y = -3x + b

I would like to plug in (0, -1) into the equation.

(-1) = -3(0) + b

-1 = b

4) Plug in the b into the equation.

y = -3x +b

y = -3x -1

can you rephrase the question ? it is unclear : -)

step-by-step explanation:

the answer is:

the answer is:

to solve the problem, we need to remember the quotient of power property, it's defined by the following relation:

if we have a quotienf of powers that have the same base, we need to keep the same base and subtract the exponent of the denominator power to the exponent of the numerator power.

so, we are given the expression:

then, calculating we have:

hence, the answer is:

have a nice day!