The first term is 8 Each term is 4 more than double the previous term.

8*2^(n-1)

Step-by-step explanation:

This is a geometric sequence since we multiply from the previous term.

a_n = a_1 * common ratio^(n-1) where a_n is the nth number and a_1 is the first.

The first term is 8, so we have

a_n = 8*<common ratio>^(n-1) = 8*2^(n-1)

the answer should be a. snail

i those same problems in math and dont know how to do them