ON wednesday Eddy goes to a velodrome to train. He cycles the first lap of the track in 25 seconds. Each lap Eddy cycles takes him 1.6 seconds longer thatn the previous lap. Required:
a. Find the time in seconds, Eddy takes to cycle his tenth lap 2
b. Eddy cycles his last lap in 55.4 seconds. Find how many laps he has cycled on wednesday.
c. Find the total time in minutes, cycled by Eddy on Sunday.

Step-by-step explanation:

The data of timing for each lap will form a arthmetic progression ( AP ) with first term as 25 s  and common difference of 1.6 s .

a )

first term a = 25

common difference d = 1.6 .

10 th term of the series can be given by following formula

a₁₀ = 25 + ( 10-1 ) x 1.6

= 25 + 1.6 x 9

= 39.4 s

b )

Let n th be the last lap

a(n) = a + ( n-1 ) x d

55.4 = 25 + ( n- 1 ) x 1.6

n - 1 = 19

n = 20 .

c )

sum of all the term of AP

=(  first term + last term ) x no of term / 2

= (25 + 55.4 ) x 20 / 2

= 804 s .

= 804 / 60 min

= 13.4 min .

answer:  

step-by-step explanation:

here x represents the height of the pole,

and, the height of the shadow of the pole is 12 feet.

also, the angle of elevation from the top of the pole is 40°,

therefore,

by the low of sine,

which is the required equation for finding the value of x,