NEED HELP ASAP Write an equation (a) in slope-intercept form and (b) in standard form for the line passing through (-1,5) and parallel to x+3y=7.

x + 3y = 5

3y = -x + 5

y = -(1/3)x + 5/3

slope = -1/3     Parallel lines have the same slope.

Now, you have a point and a slope, so use the Point-Slope form of the equation of a line.

y - y1 = m(x - x1)

y - 4 = (-1/3)(x + 2)

y - 4 = (-1/3)x - 2/3

y = (-1/3)x + 3 1/3   Slope-intercept Form

(1/3)x + y = 10/3     Multiply both sides by 3.

x + 3y = 10    Standard form

Hope this helps and don't yell at me in the comments if I am wrong

plz mark me brainliest  if I am correct

The correct answer is y= -x/3 + 14/3 and x + 3y = 14.