Mathematics, 13.01.2021 08:10 lottie2306

Please help me its solving system by substitution

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Answer from: deejay4354

(1, 4)

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

to Right

Equality Properties

Multiplication Property of EqualityDivision Property of EqualityAddition Property of EqualitySubtract Property of Equality

Algebra I

Solving systems of equations using substitution/eliminationTerms/Coefficients

Step-by-step explanation:

Step 1: Define Systems

y = x + 5

2x + y = 2

Step 2: Solve for x

Substitution

Substitute in x: 2x + x + 5 = 2Combine like terms: 3x + 5 = 2Isolate x term: 3x = -3Isolate x: x = -1

Step 3: Solve for y

Define equation: y = x + 5Substitute in x: y = -1 + 5Add: y = 4

Answer from: Quest

the system of inequity is

$y\leq -x+4$

$3y> x$

step-by-step explanation:

from the given graph it is noticed that we have two related lines. one is solid and another is dashed.

if a line passing through two points, then the equation of line is

$y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)$

the solid line passing through the points (0,4) and (4,0).

$y-4=\frac{0-4}{4-0}(x-0)$

$y=-x+4$

the related equation of solid line is $y=-x+4$ .

similarly, find the related equation of dashed line. the dashed liune passing through the points (0,0) and (3,1).

$y-0=\frac{0-1}{3-0}(x-0)$

$3y=x$

the related equation of dashed line is $3y=x$

from the given graph it is noticed that the point (0,1) lies on the shaded region, therefore the point (0,1) must be satisfied by the related equations.

check the related equations by the point (0,1).

$1=-0+4$

$1=4$

this statement is true if the sign of inequality is < instead of equality. since it is an solid line therefore the sign of inequality will be $\leq$ . the required inequality is

$y\leq -x+4$

similarly, check the second related equation.

$3(1)=0$

it is a dashed line, so this statement is true if the sign of inequality is > . the required inequality is

$3y> x$

15 points write a system of inequalities to represent the shaded portion of the graph

Answer from: Quest

idk man good luck man

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