The gym is 96 feet long 53 feet wide and 30 feet high. A bosketball is 28.5 inches in diameter. How many basketballs are needed to fill the gym?

21806 basketballs are needed to fill the gym

Step-by-step explanation:

We have to find both volumes in the same units, so I will use feet for the dimensions, the volume will be in cubic feet. Each feet has 12 inches.

Volume of the gym:

The volume of the gym(rectangular base with height) is given by the multiplication of its dimensions. So

cubic inches

Volume of the basketball:

The basketball is an sphere, so its volume is

In which r is the radius, which is half the diameter.

28.5 inches in diameter, so 2.375 feet in diameter, radius of 1.1875 feet. The volume of the basketball is:

cubic inches

How many basketballs are needed to fill the gym?

This is given dividing the volume of the gym by the volume of a basketball. So

152640/7 = 21805,7

Rouding up

21806 basketballs are needed to fill the gym

step-by-step explanation:

through just a quick inspection, one can see that the graph of this cubing function starts in quadrant iii and ends in quadrant i.   when x = 0, y = 3, so the y-intercept is (0, 3).

if graphs are part of the problem statement, share them.   .

step-by-step explanation:

given perimeter: 28cm

length: 9cm

atp,

2(l+w)=p of the reactangle

2(9+x)=28

18+2x=28

2x=28-18

x=10/2

x=5

therefore width is 5 cm