U5. Systems or Equations 3. (05.06 MC)
Moe graphed the following inequality: y > -2x + 1

Part A: Explain two mistakes that Moe made on his graph.

Part B: Is the point (-2, 6) a solution for the inequality y > -2x + 1? Justify your answer (picture below)

Does the function satisfy the hypotheses of the mean value theorem on the given interval? f(x) = 4x^2 + 3x + 4, [−1, 1] no, f is continuous on [−1, 1] but not differentiable on (−1, 1). no, f is not continuous on [−1, 1]. yes, f is continuous on [−1, 1] and differentiable on (−1, 1) since polynomials are continuous and differentiable on . there is not enough information to verify if this function satisfies the mean value theorem. yes, it does not matter if f is continuous or differentiable; every function satisfies the mean value theorem.