Find a formula for the general term an of the sequence, assuming that the pattern of the first few terms continues. (Assume that n begins with 1.) 1 2 , 1 4 , 1 6 , 1 8 , 1 10 , ...

1•2n

Step-by-step explanation:

Given the sequence if numbers

1 2 , 1 4 , 1 6 , 1 8 , 1 10 , ...

You will see that 1 is common to all the numbers, the other part of the sequence are in arithmetic progression and they are

2,4,6,8,10...

The nth term of an AP is expressed as

Tn = a+(n-1)d

a is the first term

n is the number of terms

d is the common difference

a = 2

d = 4-2 = 6-4 = 8-6 = 2

Substitute into the formula

Tn = 2+(n-1)2

Tn = 2+2n-2

Tn = 2-2+2n

Tn = 2n

Hence the nth term of the sequence is 1•2n

we know that

applying the law of sines

°

so

∠j=18°

∠k=29°

∠l=180-(18+29)=133°

the answer part a) is

the measure of angle k is  ≈29°

part b)  the measure of angle k could also be

(180-29)=151°

so

∠j=18°

∠k=151°

∠l=180-(18+151)=11°

the answer part b) is

the measure of angle k could also be 151°

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the answers are in the images, i received 100% on this assignment. hope this !