Assuming that the heights of college women are normally distributed with mean 65 inches and standard deviation 3.5 inches, what percentage of women are shorter than 68.5 inches

the percentage of women that are shorter than 68.5 inches is 84.1%

Step-by-step explanation:

Given that;

mean μ = 65

standard deviation σ = 3.5

percentage of women are shorter than 68.5 inches = ?

P( x < 68.5 ) = P(( x-μ)/σ)

we substitute

⇒ ( 68.5-65)/3.5)

⇒ P(z < 1)

form standard normal table

P( x < 68.5 ) = P(z < 1) = 0.84134 ≈ 84.1%

Therefore, the percentage of women that are shorter than 68.5 inches is 84.1%

answer:

the position of equilibrium will shift to the left.

step-by-step explanation:

the general equation for the dissociation of a weak base is

b + h₂o   ⇌   bh⁺ + oh⁻

according to le châtelier's principle, when a stress is applied to a system at equilibrium, the system will respond in a way that tends to relieve the stress.

if you apply a stress by adding more bh⁺ or oh⁻,   the system will respond by moving in a direction that gets rid of the added ions.

the position of equilibrium will shift to the left, forming more of the undissociated base.