Which function has exactly three distinct real zeros? OA. h(x) = (x-9)2(x-4)2
OB. h(x) = x(x + 7)?
O a.
C. h(x) = (x - 3)(x + 1)(x + 3)(x + 8)
OD. H(X) = (x - 2)²(x + 4)(x - 1)

H(X) = (x - 2)²(x + 4)(x - 1) has 3 zeroes, they are -4,2 and 1

fa tha first one you gonna add y to both sides

it look like this

x-y+y=6+y

x=y+6

therefore your answer is

x =y+6

fa tha second one

you gonna flip tha equation

it gonna look like x-4y=y

then add 4 to both sides

it gonna look like tha

x-4 +4 =y +4

so therefore tha answer is x=y+4

step-by-step explanation: