Which table has a constant of proportionality between y
yy and
x
xx of
3
4
4
3

start fraction, 3, divided by, 4, end fraction?
Choose 1
Choose 1

(Choice A)
A
x
xx
y
yy
8
88
6
66
9
99
27
4
4
27

start fraction, 27, divided by, 4, end fraction
10
1010
15
2
2
15

start fraction, 15, divided by, 2, end fraction

(Choice B)
B
x
xx
y
yy
3
33
3
4
4
3

start fraction, 3, divided by, 4, end fraction
4
44
1
11
5
55
5
4
4
5

start fraction, 5, divided by, 4, end fraction

(Choice C)
C
x
xx
y
yy
10
1010
19
2
2
19

start fraction, 19, divided by, 2, end fraction
11
1111
41
4
4
41

start fraction, 41, divided by, 4, end fraction
12
1212
11
1111

Btw this is from khan academy.

24/56=hx^7

step-by-step explanation:

percentage - 25%

probability - 0.25

we know,

total amount of students in class = 20

total boys = 10

total girls = 10

no of girls who wear glasses = 10/2 = 5

probability of choosing a girl with glasses is =

number of girls wearing glasses/total number of students in the class = 5/20

thus, percentage of selecting a girl wearing glasses will be

= 5/20 × 100

= 5 × 5

25%

therefore,

probability will be 0.25

happy to

pls mark as brainliest

3. (5x + 1) - (-10x + 6)

simplify the answer choice. combine like terms. remember to distribute the negative to the terms inside the second parenthesis. also remember that two negatives = one positive, and one of each sign = negative.

- (-10x + 6) = + 10x - 6

simplify. combine like terms:

5x + 1 + 10x - 6

5x + 10x + 1 - 6

15x - 5

∴ it is your answer

~

a

step-by-step explanation: