the sum of the digits of a two-digit number is 11 the tens digit is one less thn three times the ones didgit find the original number

The original number is 83

Step-by-step explanation:

let the number be ab

Sum of the two is 11

a + b = 11

tens digit a is one less than 3 times the ones digit

3b - a = 1

a = 3b - 1

3b -1 + b = 11

4b = 11 + 1

4b = 12

b = 12/4

b = 3

a = 3b - 1

a = 3(3) - 1

a = 9-1

a = 8

sss (side, side, side)

sas (side, angle, side)

asa (angle, side, angle)

aas (angle, angle, side)

hl (hypotenuse, leg)

the answer is ! ?