(100 POINTS PLUS BRAINIEST IF CORRECT I NEED HELP FAST) The table below shows all of the possible outcomes for rolling two six-sided number cubes. A table with 36 possible outcomes. There are 9 desired outcomes. What is the probability of rolling an even number first and an odd number second?
StartFraction 1 over 9 EndFraction
StartFraction 1 over 6 EndFraction
One-fourth
One-half

The image is missing, we have attached the image.

The of getting an even number in first and an odd number second is 1/4 or 0.25

Step-by-step explanation:

Given,

Total number of outcomes = 36

We have to find the probability of rolling an even number first and an odd number second.

Solution,

Firstly we will find out the possible outcomes;

(2,1)(2,3)(2,5)(4,1)(4,3)(4,5)(6,1)(6,3)(6,5)

So the total number of outcomes = 9

Now according to the formula of probability, which is;

P(E)= total number of possible outcomes/total number of outcomes

Now on putting the values, we get;

P(of getting an even number in first and an odd number second)= 9/36 = 1/4 =0.25

Hence The of getting an even number in first and an odd number second is

1/4 or 0.25.

Hope this help

step-by-step explanation:

in the absence of parentheses, i will have to make some assumptions:   i interpret your (3x+5/y^6)(4y^3/5)​ to mean:

3x + 5     4y^(3/5)       (3x + 5)(4)

* =

    y^6             1               y^(6-3/5)

if this is not what you expected, repost your question using parentheses to indicate whether you meant

4y^3

    or   4y^(3/5)

    5