What is the y-coordinate of the point that divides the directed line segment from J to k into a ratio of 5:1?
2
1
TK (72)
ya
= ( mooi Jiva - vi) + 1
1 2 3
4 5
6 7 8 9 10 11 x
-1
-2
-3
-8
05
0 0
5
-6
-7
-8
-9
-10
J (1.-10)
-11

left 3, up 4

step-by-step explanation:

just count the values of x & y of the vertex of the graph and see how many units in the x and y direction will get you from the f(x) graph to the f(x) graph

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option

the answer is 48m^2!

step-by-step explanation: