(please help!)Abigail invested $2,900 in an account paying an interest rate of 2.8% compounded quarterly. Assuming no deposits or withdrawals are made, how long would it take, to
the nearest year, for the value of the account to reach $4,050?

Step-by-step explanation:

4050 = 2900 (1 + 0.028/4)^4t

4050 = 2900 (1.007)^4t

Divide all by 2900

1.3965517 = 1.007^4t

TURN LOG

log (1.3965517) = log (1.007^4t)

47.8819724 = 4t

11.9704931 = t

Round to nearest year = 12

T = 12

step-by-step explanation:

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3