basket contains 7 green apples, 9 red apples, 10 nectarines, and 10 oranges. Sandy randomly chooses a piece of fruit, eats it, then selects another. Find the probability of selecting a red apple then a oranges?

So the probability is 1/14 or 7.14%

Step-by-step explanation:

First lets  calculate the total number of fruits:

Now, calculating the probability of the first fruit being a red apple, we have 9 red apples among 36 fruits, so the probability is 9/36.

Then the probability of the second fruit being an orange will be 10/35 , since we will have 10 oranges among 35 fruits.

Finally the final probability is the product of these two probabilities , so we have:

So the probability is 1/14 or 7.14%

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y > 1/3x

y < = -x + 4

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