The graph of which function is decreasing over the interval (–4, ∞)?

f(x) = (x + 4)2 + 4
f(x) = –(x + 4)2 + 4
f(x) = (x – 4)2 – 4
f(x) = –(x – 4)2 – 4

Ok, logic
all of them are parabolas

1st and 3rd are opening up, so they defenitely increase, so no

decraseing
the vertex hs to be be at x=-4
y=a(x-h)^2+k
h has to be -4
y=a(x+4)^2+k
the answer is 2nd one or f(x)=-(x+4)^2+4

128/3reason being 5 and 1/3 = 16/316/3 • 2/3 = 32/31 and 1/3 = 4/3 32/3 • 4/3 this will equal 128/3