What is the equation of the line that is perpendicular to the line through (1,-4) and (-2,2) and passes through the x-intercept of that line?

y=-x+

Step-by-step explanation:

First, calculate the slope of the line that is perpendicular to the equation of line we are asked to find

m=(y2-y1)/(x2-x1)

  =(2-(-4))/(-2-1)

  =6/-3

  =-2

in this equation the slope is 2, and to find the first equation, use y=mx+b

use the point (1, -4) to find b

-4=(2)(1)+b

-4=2+b

b=-6

the first equation of the line is y=2x-6

to find the x intercept of that line substitute 0 for y

0=2x-6

2x=6

x=3

the slope of a line perpendicular to this would be the opposite reciprocal of the slope which would be equal to -1/2

for the second equation of the line to pass thorugh the x-intercept of the first line, it must pass through (3, 0), so substitute and solve for b

y=mx+b

0=(-1/2)(3)+b

b=3/2

thus the equation of the line that is perpendicular to the line through (1,-4) and (-2, 2) and passes through the x intercept of that line is y=-x+3/2

hey there!

if she's saving for six months, let's divide the total number we need for the trip by six, dividing it into the amount that needs to be saved for each month.

500 ÷ 6 =

she needs to save at least this amount each month, so we should use this symbol: ≥

let x be the amount she saves each month.

your final answer is x ≥

hope this !

15 units use socratic

step-by-step explanation: 15 units