Find the equation of the line passing through (1,4) and (-2,-1).

y=5/3x+7/3

Step-by-step explanation:

Here are the points: (1,4) and (-2, -1)

let's first find the slope, which is with the equation m=(y2-y1)/(x2-x1) (m is the slope)

label the points:

x1=1

y1=4

x2=-2

y2=-1

now subsitute into the equation

m=(-1-4)/(-2-1)

m=-5/-3

m=5/3

the slope of the line 5/3

Here's the equation so far:

y=5/3x+b (b is a place holder)

we can substitute either one of the points into the equation so far to find b, because the line will pass through both of them>

let's use (1,4) as an example

4=5/3(1)+b

4=5/3+b

subtract 5/3 from both sides

7/3=b

Now, put it all together:

y=5/3x+7/3

Hope this helps!