1) Ben has 15 coins, all dimes and quarters, worth $2.55. How many dimes and how many quarters does Ben have?

Ben has 8 dimes and 7 quarters.

Step-by-step explanation:

Given that:

Number of coins = 15

Worth of coins = $2.55 = 2.55 * 100 = 255 cents

Let,

x be the number of dimes

y be the number of quarters

According to given statement,

x+y=15     Eqn 1

10x+25y=255     Eqn 2

Multiplying Eqn 1 by 10

10(x+y=15)

10x+10y=150     Eqn 3

Subtracting Eqn 3 from Eqn 2

(10x+25y)-(10x+10y) = 255 - 150

10x+25y-10x-10y=105

15y=105

Dividing both sides by 15

Putting y=7 in Eqn 1

x+7=15

x=8

Hence,

Ben has 8 dimes and 7 quarters.

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?