Please help now pleasee A tree casts a shadow 7.5 feet long at the same time that a 5 foot tall woman casts a shadow 3 feet long. How tall is the tree?

The tree is 12.5ft Step-by-step explanation: 1.  TREE'S HEIGHT over TREE'S SHADOW equals WOMAN'S HEIGHT over WOMAN'S SHADOW

2.  TREE'S HEIGHT over WOMAN'S HEIGHT equals TREE'S SHADOW over WOMAN'S SHADOW

or some other ways as long as you pair them up by 'height', or pair them up by

'shadow'.  {But don't get them criss-crossed)

Let TREE's HEIGHT = t.

A tree casts a shadow 7.5 ft long

TREE'S SHADOW = 7.5

at the same time that

a woman 5 ft tall

WOMAN'S HEIGHT = 5

casts a shadow 3 ft long.

WOMAN'S SHADOW = 3

So if you use

1.  TREE'S HEIGHT over TREE'S SHADOW equals WOMAN'S HEIGHT over WOMAN'S SHADOW

cross-multiply:

3t = 37.5

 t = 12.5

or if you use

2.cross-multiply

3t = 37.5

 t = 12.5

Either way, the tree is 12.5 feet tall.    

I got 12.5 too

Step-by-step explanation:

theres no picture: /

step-by-step explanation:

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet